If you can solve the above, you should be able to solve these too (without using calculator):
Find the value of:
(a) 3x, where x = 4 + log3 2. (My question)
(b) 2z, where z = 5 + log2 3 (IGCSE Cambridge Add-Maths 0606, Yr 2010/Summer/p22, Q10(b))
I will post their answers in a week or so. Meanwhile, you may post your answers by way of comments to this post. Have fun with maths!
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29.04.2014
Have fun with maths!
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(1.5.2014)
Brain Teaser 2B (requires slightly more skill than Brain Teaser 2)
Find the value of:
(a) 3x, where x = 4 + log3 2. (My question)
(b) 2z, where z = 5 + log2 3 (IGCSE Cambridge Add-Maths 0606, Yr 2010/Summer/p22, Q10(b))
I will post their answers in a week or so. Meanwhile, you may post your answers by way of comments to this post. Have fun with maths!
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29.04.2014
My Proposed Solutions to These Questions:
Find the value
of:
(Lead Question): ex, where x = 4 + ln
2
(a) 3x, where x = 4 + log3 2. (My question)
(b) 2z, where z = 5 + log2 3 (IGCSE Cambridge Add-Maths 0606, Yr 2010/Summer/p22, Q10(b))
(a) 3x, where x = 4 + log3 2. (My question)
(b) 2z, where z = 5 + log2 3 (IGCSE Cambridge Add-Maths 0606, Yr 2010/Summer/p22, Q10(b))
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For the lead question:
Since x = 4 + ln 2,
therefore: ex = e(4 + ln 2) = e4
x eln 2 ..............Law of index: b(m + n) = bm x bn
Now: let y = eln 2
ln both sides:
ln y = ln 2
therefore: y = 2 = eln 2 (Hence,
remember: eln a = a; 10lg b = b; etc.)
Hence, ex = e(4 + ln 2) =
e4 x eln 2 = 2e4 (Answer)
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(a)
Since
x = 4 + log3 2
therefore:
3x = 3^(4 + log3 2)
= 34 x 3^log3 2 = 34 x 2 (see above)
3x = 81 x 2 = 162 (Answer)
(b)
Since z = 5 + log2 3
therefore: 2z = 2^(5 + log2 3) =
25 x 2^log23 = 25 x 3
2z = 32 x 3 = 96 (Answer)
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So, remember:
·
eln a = a
·
10lg b = b
·
b^logb c = c
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(1.5.2014)
Brain Teaser 2B (requires slightly more skill than Brain Teaser 2)
Find the exact value of:
1) 3x , where x = 2 + log9 3
2) 2y , where y = 3 + log8 2
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1) 3x , where x = 2 + log9 3
2) 2y , where y = 3 + log8 2
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